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    Any problem solvable in deterministic polynomial time is ... — Carmelics
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    Home/Modality & Possibility
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    Supports→P is a subset of NP (P ⊆ NP)

    Any problem solvable in deterministic polynomial time is therefore solvable in nondeterministic polynomial time

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    Every deterministic Turing machine is by definition a special case of a nondeter...P is a subset of NP (P ⊆ NP)

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    Any problem solvable in deterministic polynomial space is therefore so...93%Any problem solvable in deterministic or probabilistic polynomial time...87%SAT can be solved in polynomial time by a non-deterministic Turing mac...86%If P = NP, then every problem in NP is solvable in polynomial time85%

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    Similarly, parts i) and ii) respectively implies that \(\textbf{P} \subsetneq \textbf{EXP}\) and \(\textbf{NP} \subsetneq \textbf{NEXP}\). And it similarly follows from part iii) that \(\textbf{L} \subsetneq \textbf{PSPACE}\). Note that since every deterministic Turing machine is, by definition, a non-deterministic machine, we clearly have \(\textbf{P} \subseteq \textbf{NP}\) and \(\textbf{PSPACE} \subseteq \textbf{NPSPACE}\). 2 Suppose that \(f(n)\) is both time and space constructible. Then

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