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    As n increases, deciding membership in TWO PLAYER SAT_n b... — Carmelics
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    Supports→The Polynomial Hierarchy does not collapse to any finite level (Σ^P_k ⊊ Σ^P_{k+1} for all k)

    As n increases, deciding membership in TWO PLAYER SAT_n becomes harder, analogous to how determining winning strategies for longer games of Go or chess becomes harder

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    TWO PLAYER SAT_n is complete for Σ^P_n in the Polynomial HierarchyThe Polynomial Hierarchy does not collapse to any finite level (Σ^P_k ⊊ Σ^P_{k+1...The assertion PH = Σ^P_k for some k is equivalent to asserting that n-round veri...This equivalence runs contrary to expectation

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    As n increases, deciding membership in TWO PLAYER SAT_n appears to bec...97%Deciding membership in TWO PLAYER SAT_n becomes more difficult as n in...85%As the number of quantifier alternations n increases, deciding members...83%Determining whether a player has a winning strategy becomes more diffi...82%

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    We then define \(\Sigma^P_{n+1}\) to be the class of problems of the form \(X = \{x \mid \exists y \leq p(\lvert x\rvert) R(x,y)\}\) where \(R(x,y) \in \Pi^P_{n}\) and \(\Pi^P_{n+1}\) to be the class of problems of the form \(X = \{x \mid \forall y \leq q(\lvert x\rvert) S(x,y)\}\) where \(S(x,y) \in \Sigma^P_{n}\) and \(p(n)\) and \(q(n)\) are both polynomials. \(\Delta^P_n\) is the set of problems which are in both \(\Sigma^P_{n}\) and \(\Pi^P_{n}\). 1 that \(\Sigma^P_1 = \textbf{NP}\) and \(\

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