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    Home/Original/inverse
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    Inverse View

    It is not the case that BHP is NP-complete

    Aggregate Confidence:0%

    Reasons For

    2 perspectives
    Reason for 1 of 2
    ?
    • 1.NP-completeness proofs require a precise formal definition of BHP, yet 'Bounded Halting Problem' admits multiple non-equivalent formulations in the literature.
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    • 2.If BHP is defined over Turing machines with bounded steps, the reduction from SAT presupposes a fixed encoding scheme whose choice affects the complexity classification.
      ?

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    • 3.Complexity classifications are encoding-relative, so claiming BHP is NP-complete without specifying the encoding is a category error, not a theorem (cf. Papadimitriou 1994).
      ?

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    Reason for 2 of 2
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    • 1.NP-hardness is established via polynomial-time many-one reductions, which themselves presuppose P ≠ NP is not provably false—a claim independent of ZFC under some interpretations.
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    • 2.If NP-completeness proofs rely on unresolved foundational assumptions about computational complexity classes, the claim 'BHP is NP-complete' is conditionally established at best, not categorically so.
      ?

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    Reasons Against

    2 perspectives
    Reason against 1 of 2
    ?
    • 1.BHP is in NP
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    • 2.BHP is hard for NP
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    Reason against 2 of 2
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    • 1.BHP is in NP
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    • 2.BHP is NP-hard
      ?

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