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    By repetition, all instances of a0 across the copies must... — Carmelics
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    Supports→Γ2 is not consistently colourable.

    By repetition, all instances of a0 across the copies must share the same colour.

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    Related propositions within the same area of thought.
    Having p0, q0, r0 all white or all black is inconsistent with exactly one of the...In Γ1 with θ=18°, points a0 and a9 must have equal colour.In Γ2, point a9 of one copy of Γ1 is identified with point a0 of the next copy.Points p0, q0, and r0 are identified with points a0, so they must all be the sam...
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    The colouring constraint requires that exactly one of p0, q0, r0 be white.Γ2 is constructed from copies of Γ1 with θ=18°.Γ2 is not consistently colourable.

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    Points p0, q0, and r0 are identified with points a0, so they must all ...79%In Γ2, point a9 of one copy of Γ1 is identified with point a0 of the n...74%Assume for reductio ad absurdum that a0 and a9 have different colours ...74%By NC, occurrences of the same ray in different columns receive the sa...73%

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    However, although Γ2 is constructible it is not consistently colourable. From the first step we know that a copy of Γ1 with θ=18° requires that points a0 and a9 have equal colour. Now, since a9 in one copy of Γ1 is identical to a0 in the next copy, a9 in the second copy must have the same colour as a0 in the first. Indeed, by repetition of this argument all instances of a0 must have the same colour. Now, p0, q0, r0 are identified with points a0, so they must be either all white or all bla

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