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    L is too 'thin' to contain the ultrafilter that witnesses... — Carmelics
    Home/Modality & Possibility
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    Supports→L cannot recognize that κ is a measurable cardinal

    L is too 'thin' to contain the ultrafilter that witnesses the measurability of κ

    Modality & PossibilityTruth & Knowledge
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    L cannot recognize that κ is a measurable cardinalRecognizing measurability requires the existence of an ultrafilter witnessing th...

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    Recognizing measurability requires the existence of an ultrafilter wit...87%L cannot recognize that κ is a measurable cardinal68%Since κ is strongly inaccessible in V and (Vκ+1)^M = Vκ+1, M also thin...67%M thinks there is a strongly inaccessible cardinal (namely κ) below j(...66%

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    In fact, Scott showed that (in contrast to the small large cardinals) measurable cardinals cannot exist in Gödel's constructible universe. Let us be precise about this. Let V=L be the statement that asserts that all sets are constructible. Then for each small large cardinal axiom φ (to be precise, those listed above) if the theory ZFC+φ is consistent then so is the theory ZFC+φ+V=L. In contrast, the theory ZFC + “There is a measurable cardinal” proves ¬V=L. This may seem somewhat counterintu

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