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    Measurements of P and Q are incompatible. — Carmelics
    Home/Perception
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    Challenges→We have no reason to assume that v(f(Q)) = v(g(P)).

    Measurements of P and Q are incompatible.

    Modality & PossibilityPerception
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    PerceptionModality & Possibility

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    Truth & Knowledge3 linkedSkepticism

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    We have no reason to assume that v(f(Q)) = v(g(P)).v(f(Q)) and v(g(P)) are therefore outcomes of different measurement situations.v(f(Q)) is determined by measuring Q.v(g(P)) is determined by measuring P.

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    FACTORIZATION is in both NP and coNP.86%Oscar and Oscar− are distinct at t85%Oscar and Oscar− are distinct at t'85%Therefore Rab and Rba would be identical, which contradicts their dist...85%

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    Finally, we might accept VD and VR, but deny that our construction of an observable f(Q) is unambiguous. Thus, though f(Q) and g(P) are mathematically identical, we could assume that they correspond to different observables, arguing that an actual determination of v(f(Q)) must proceed via measuring Q, but the determination of v(g(P)) involves measuring P which is incompatible with Q. Since v(f(Q)) and v(g(P)) are thus outcomes of different measurement situations, there is no reason to assume tha

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