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Inverse View
It is not the case that P ≠ NP if and only if there exists a class of ordered structures definable in existential second-order logic that is not definable by any formula of FO(LFP).
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Reasons For
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Reason for 1 of 2
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1.
Descriptive complexity results like Fagin's theorem presuppose fixed finite ordered structures, but the P vs NP problem ranges over all computational models regardless of representational assumptions.
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2.
The logical characterization via SO∃ and FO(LFP) is order-sensitive: without a built-in linear order, FO(LFP) fails to capture P, undermining the biconditional's claim to equivalence with the full complexity-theoretic question.
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3.
Immerman and Vardi's theorem requires that order be present in the structure, so the logical reformulation captures only a restricted variant of P vs NP, not the general problem as standardly posed.
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Reason for 2 of 2
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1.
The biconditional conflates provability within a descriptive complexity framework with the truth of an independent computational conjecture, committing a use-mention error about mathematical equivalence.
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2.
Razborov and Rudich's natural proofs barrier suggests that any combinatorial or logical property definably separating P from NP would itself be constructible by efficient algorithms, creating a self-undermining circularity in logical separation arguments.
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Reasons Against
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Reason against
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1.
NP is captured over ordered structures by SO∃.
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2.
P is captured over ordered structures by FO(LFP).
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3.
If P = NP then every property expressible in SO∃ would be expressible in FO(LFP), and conversely.
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