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    Simply setting down a recursive definition does not, by i... — Carmelics
    Home/Moral Responsibility
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    Supports→If a model of computation does not natively support recursion, then defining a function h(y) by primitive recursion over a base function g(y) computable in that model provides no a priori assurance that h(y) is itself computable in that model.

    Simply setting down a recursive definition does not, by itself, establish computability within a given model.

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    Moral ResponsibilityTruth & Knowledge

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    In the case that \(f(y)\) and \(g(y)\) are primitive recursive, we have remarked that it is possible to show that there exists a unique function \(h(y)\) satisfying (\ref{recex}) by an external set-theoretic argument. But we may also consider the case in which \(g(y)\) is assumed to be computable relative to a model of computation \(\mathbf{M}\) which differs from the partial recursive functions in that it does not natively support recursion as a mode of computation—e.g., the Turing Machine mode

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