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It is not the case that SPACE(s1(n)) is a proper subset of SPACE(s2(n)) when s2(n) grows sufficiently faster than s1(n)
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Reasons For
2 perspectives
Reason for 1 of 2
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1.
The space hierarchy theorem's proof relies on a diagonalization argument that presupposes a universal TM can simulate any TM with bounded overhead.
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2.
The simulation overhead assumption embeds a non-trivial empirical claim about machine architecture that is not derivable from pure mathematical definitions of SPACE classes.
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3.
If the overhead of universal simulation is not tightly bounded, the strict separation between SPACE(s1(n)) and SPACE(s2(n)) may not hold for all constructible function pairs satisfying the ratio condition.
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Reason for 2 of 2
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1.
Space constructibility is a non-trivial precondition: not all mathematically well-defined functions s(n) >= n are space constructible in the required sense.
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2.
The claim's scope is implicitly restricted to a proper subset of function pairs, making the theorem's generality philosophically overstated when presented without that qualification.
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Reasons Against
1 perspective
Reason against
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1.
s1(n) and s2(n) are space constructible functions with s2(n) >= s1(n) >= n
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2.
The limit of s1(n) / s2(n) as n approaches infinity equals 0
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