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    Every problem X in NP is polynomial-time reducible to SAT — Carmelics
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    Supports→SAT is NP-complete

    Every problem X in NP is polynomial-time reducible to SAT

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    Related propositions within the same area of thought.
    For any NP machine N and input x, a propositional formula φ_{N,x} can be constru...SAT is NP-completeSAT is in NP

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    Every problem in NP is polynomial-time reducible to any NP-complete pr...96%If a problem X is polynomial time reducible to a problem Y, then an ef...89%3-SAT is polynomial-time reducible to INDEPENDENT SET86%Every problem X in NP is polynomial-time reducible to SAT via a reduct...86%

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    We have already seen that \(\sc{SAT}\) is in \(\textbf{NP}\). In order to demonstrate Theorem 3.4 it thus suffices to show that all problems \(X \in \textbf{NP}\) are polynomial time reducible to \(\sc{SAT}\). Supposing that \(X \in \textbf{NP}\) there must again be a non-deterministic Turing machine \(N = \langle Q,\Sigma,\Delta,s \rangle\) accepting \(X\) with polynomial time complexity \(p(n)\). The proof of Theorem 3.4 then proceeds by showing that for all inputs \(x\) of length \(n\) for \(

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