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    If PH = PSPACE, then PH would have a complete problem (TW... — Carmelics
    Home/Modality & Possibility
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    Supports→PH is expected to lack complete problems, unlike PSPACE

    If PH = PSPACE, then PH would have a complete problem (TWO PLAYER SAT)

    Modality & PossibilityTruth & Knowledge
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    Modality & PossibilityTruth & Knowledge

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    Skepticism2 linked

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    PH is expected to lack complete problems, unlike PSPACEPH is widely believed to differ from PSPACEThe existence of a complete problem for PH would imply PH collapses, which is co...

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    If PH = PSPACE, PH would have complete problems (since PSPACE has comp...96%If PH = PSPACE, then TWO PLAYER SAT would be complete for PH87%If PH = PSPACE, then TWO PLAYER SAT would be complete for PH (since it...87%If P = NP then every problem in NP is also in P86%

    Source

    AI-extracted
    SEP: computational-complexity
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    Consider, for instance the following variation on the standard rules of Go: (i) the game is played on an \(n \times n\) board; (ii) the winner of the game is the player with the most stones at the end of \(n^2\) rounds. e. the player who moves first)? [30] What these games have in common is that the definition of a winning strategy for the player who moves first involves the alternation of existential and universal quantifiers in a manner which mimics the definition of the classes \(\Sigma^P_n\)

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