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    If PH = PSPACE, then TWO PLAYER SAT would be complete for... — Carmelics
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    Supports→The Polynomial Hierarchy (PH) is properly contained in PSPACE, i.e., PH ⊊ PSPACE

    If PH = PSPACE, then TWO PLAYER SAT would be complete for PH (since it is complete for PSPACE)

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    Related propositions within the same area of thought.
    It is contrary to expectation that longer verification games are no harder than ...Since PH is defined as the union of all Σ^P_k classes, TWO PLAYER SAT ∈ Σ^P_k fo...The Polynomial Hierarchy (PH) is properly contained in PSPACE, i.e., PH ⊊ PSPACEThis would imply that determining whether Verifier has a winning strategy for n-...

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    If PH = PSPACE, then TWO PLAYER SAT would be complete for PH98%BHP (Bounded Halting Problem) is NP-complete87%If PH = PSPACE, then PH would have a complete problem (TWO PLAYER SAT)87%If PH = PSPACE, PH would have complete problems (since PSPACE has comp...86%

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    SEP: computational-complexity
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    [26] A complexity class which is likely to be properly contained in \(\textbf{EXP}\) but which still contains many apparently infeasible problems which arise in computational practice is \(\textbf{PSPACE}\). e. a statement of the form \(Q_1 x_i \ldots Q_n x_n\psi\) where \(Q_i = \exists\) or \(\forall\) and \(\psi\) is a formula of propositional logic containing the propositional variables \(x_1,\ldots,x_n\) which are treated as bound by these quantifiers. g. \(\forall x_1 \exists x_2 (x_1 \vee

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