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    If S and S' satisfy all functional and structural criteri... — Carmelics
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    Supports→Carter's argument against the claim that S and S' are identical fails

    If S and S' satisfy all functional and structural criteria for ship-identity equally well, the burden of proof lies with Carter to supply a non-arbitrary reason to prefer O's identity with the original, which he does not provide.

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    Key Terms

    Carter(the specific philosopher being critiqued here)
    A philosopher (William R. Carter) who wrote about the Ship of Theseus problem and how we determine ship identity.
    Functional criteria(the standard used to judge whether animals are truly using concepts)
    The practical standards or requirements needed to say something actually works or serves a purpose—focusing on what it *does* rather than what it's made of.
    Non-arbitrary(describing whether there's a fair, logical way to measure contributions)
    A way of deciding something that's based on clear, objective reasons rather than just picking whatever you want without justification.
    S and S'(used to compare two potential ships)
    Symbols used in logic to represent two different objects or scenarios being compared; the prime mark (') just means 'another version of S'.

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    Ship-identity(the core problem being discussed)
    The philosophical question of what makes a ship 'the same ship' over time, especially when parts are replaced or it's rebuilt.
    Structural criteria(as used in Young's framework)
    A set of standards or conditions for identifying how systems and institutions create unfair treatment, rather than just individual bad behavior.
    burden of proof(Used to frame the default presumption against coercive institutional structures.)
    The obligation on institutions employing authority, hierarchy, or domination to demonstrate that such arrangements are justified given existing conditions.

    Connections

    2 topics

    Modality & Possibility1 linkedPersonal Identity1 linked

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    Carter's argument against the claim that S and S' are identical fails

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